| The diagram
below shows the rate of an enzyme controled reaction. The
solid line indicates the normal relationship between rate
and substrate concentration and the dotted line indicates
the relationship when a competitive inhibitor is added. |
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| a.i) |
Explain how a
competitive inhibitor acts |
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- It is similar
in shape to the substrate
- Therefore fits
into the active site
- Thus blocking
it preventing substrate entering and slowing
reaction rate (any 2)
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(2) |
| ii) |
Explain why in the
graph above the inhibitor is a competitive inhibitor? |
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- The graph shows
that at high substrate concentration the effect
of the inhibitor is removed
- This is because
as soon as an active site becomes free it is
filled with another substrate molecule
|
(2) |
| The graph below
shows the relationship between rate of reaction and
temperature of most enzyme reaction. |
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| b. |
Explain why
the relationship is that shown on the graph. |
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- Initially as
the temperature increases the amount of kinetic
energy of the particles increases
- Therefore there
are more successful collisions per unit time
- This continues
until the rate is at its greatest (the optimum
temperature)
- At temperatures
higher than this Hydrogen bonds holding the
polypeptide chains together begin to break
- This affects
the tertiary structure of the enzyme (denatures
it)
- This changes
the shape of the active site
- Substrate can
no longer fit, therefore rate decreases
- This continues
until 100% of the enzyme molecule are denatured
and the rate of reaction falls to zero
(any five)
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(5) |